AB = CD = √8 ≈ 2.8 units
BC = AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = 3.92 units²
Perimeter of the rectangle ABCD = 8.4 units
<h3>How to Find the Area and Perimeter of a Rectangle?</h3>
Given the coordinates of vertices of rectangle ABCD as:
- A(0,2)
- B(2,4)
- C(3,3)
- D(1,1)
To find the area and perimeter, use the distance formula to find the distance between A and B, and B and C.
Using the distance formula, we have the following:
AB = √[(2−0)² + (4−2)²]
AB = √[(2)² + (2)²]
AB = √8 ≈ 2.8 units
CD = √8 ≈ 2.8 units
BC = √[(2−3)² + (4−3)²]
BC = √[(−1)² + (1)²]
BC = √2 ≈ 1.4 units
AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = (AB)(BC) = (2.8)(1.4) = 3.92 units²
Perimeter of the rectangle ABCD = 2(AB + BC) = 2(2.8 + 1.4) = 8.4 units
Learn more about the area and perimeter of rectangle on:
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The answer would be 1.40. The 3 significant figure are 1.39 and it wants us to round so we look at the 8 in 1.3981 and since 8 > 5 we know to round up.
Answer:
this Answer is
Step-by-step explanation:
2(3x+1) ≤ 20
6x+1≤20
6x≤19
x≤19/6
4(x−1)<2
4x-1<2
4x< 3
x< 3/ 4
Answer:
1
Step-by-step explanation:
f(x) = e^(8x⁵−8x)
Since f(x) is continuous:
lim(x→1) f(x) = f(1)
lim(x→1) f(x) = 1
