as you already know, we start off by doing a quick switcheroo on the variables, and then we solve for y to get the inverse,

and if you run a vertical line test on that expression, you'll find that it doesn't pass it, meaning is not a function.
What power? ce <span>putere?</span>
Answer:
5 seconds
Step-by-step explanation:
In order to find the time when it landed, we will have to find the x-intercepts.
Equation given to us : -16t² + 48t + 160
Let's take the GCD, which is -16.
-16( t² - 3t - 10 )
Factoring what's inside the brackets, we get the x-intercepts.
What multiples to -10 but adds up to -3? The numbers are -5 and 2
-16 ( t - 5 ) ( t - 2 )
X-intercepts are t - 5 and t - 2
Which is 5 and 2 seconds. But one of this is an extraneous solution and that is 2.
If we substitute the value of 2 in the equation, we will not get 0.
During the x-intercept, the x has a value and y is 0. If we substitute 5 ans x. we will get y as 0.
Hence, the answer is 5 seconds.
The angles of a quadrilateral add to 360, so we can solve for x by adding the 4 angle measures together and setting it equal to 360:
90 + 140 + (x - 10) + (x - 20) = 360
Combine like terms:
230 + 2x - 30 = 360
200 + 2x = 360
200 - (200) + 2x = 360 - (200)
2x = 160
Divide both sides by 2:
2x/(2) = 160/(2)
x = 80
Answer:
29°C
Step-by-step explanation:
Given the following
Highest temperature= 11°C
lowest temperature
Drop in temperature = highest - lowest
Drop in temperature = 18 - ()-11)
Drop in temperature = 18 + 11
Drop in temperature = 29°C