Answer:
rounding to the nearest tenth
Step-by-step explanation:
No, you cant trisect a line with a straight edge and a compass.
Answer:
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Step-by-step explanation:
Can you please provide the question
First find the slope between any two points:

Where

are the two points
So calculating the slope:

So the slope is

And our equation will be in the format of

where
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and

So, now we have half of the equation:

Now to calculate b, we can plug in a point

and solve for b.
So

Lets use the point

So:

And then:

So our final equation is