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3 years ago

What is the length of a diagonal cube with a side length of 10cm?

Mathematics

1 answer:

Blizzard [7]3 years ago

5 0

Answer:

Step-by-step explanation:

diagonal= $\sqrt{10^2+10^2}$

diagonal= $\sqrt{200}$

diagonal=14.1421356

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The average weight of David, Esther, and Henry is 42.6 kg. Esther is twice as heavy as Henry. David is 5.2 kilograms lighter tha

kari74 [83]

Answer:

53.2 kg

Step-by-step explanation:

Let E represent Esther's weight. Then Henry's weight is E/2, and David's weight is E-5.2. Their average weight is ...

((E-5.2) + E + (E/2))/3 = 42.6

2.5E -5.2 = 127.8 . . . . . . . . . . multiply by 3, simplify

2.5E = 133 . . . . . . . . . . . . . . . . add 5.2

E = 133/2.5 = 53.2 . . . . kg

Esther's weight is 53.2 kg.

7 0

3 years ago

4x+5y=20 need help solving x and y intercept plotting

Mrrafil [7]

Answer:

(Hope this helps can I pls have brainlist (crown)☺️)

Step-by-step explanation:

To find the x-intercept, substitute in 0 for y and solve for x To find the y-intercept, substitute in 0 for x and solve for y.

Slope: $m=-\frac{4}{5}$

x-intercept(s): ( 5 , 0 )

y-intercept(s): ( 0 , 4 )

8 0

3 years ago

Can someone help me answer this, I think its A but I'm not to sure.

Annette [7]

Yes I think (A) is the correct answer

4 0

3 years ago

If f'(x)=2/x and f(sqrt(e))=5, then f(e)=

docker41 [41]

$f'(x)=\dfrac2x$
$\implies f(x)=\displaystyle\frac2x\,\mathrm dx=2\ln|x|+C$

$f(\sqrt e)=5\implies 5=2\ln|\sqrt e|+C$
$\implies 5=\dfrac22\ln e+C$
$\implies C=4$
$\implies f(x)=2\ln|x|+4$
$\implies f(e)=2\ln|e|+4=6$

3 0

3 years ago

HELPPPPPPPPPPPP!!!!!

kykrilka [37]

9=3^2

3^(2x)=(3^2)^(3x-4)
3^(2x)=3^(6x-8)
2x=6x-8
0=4x-8
8=4x
2=x

6 0

3 years ago

Read 2 more answers