Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
X + (-y) = -2.3 + ( - (-5.9) ) = -2.3 + 5.9 = 3.6
Answer:
- Length is <u>20 cm</u>
- Breadth is <u>10 cm</u>
Step-by-step explanation:
<h3>According to the Question</h3>
It is given that,
- Length of rectangle is twice as its breadth
- Perimeter of Rectangle = 60cm
We have to calculate the length and
breadth of the rectangle.
Let the breadth be x cm.
then,
Length be 2x cm.
Calculating the length and breadth-
- Perimeter of Rectangle = 2(Length+breadth)
By putting the value we get-
→60 = 2(2x+x)
→60 = 2(3x)
→60 = 6x
→x = 60/6
→ x = 10 cm
Since, breadth is <u>10</u> cm.
Therefore, Length = 2x = 2×10 = 20 cm.
- Hence, the length and breadth of rectangle is 20 cm & 10 cm respectively.
Answer:
why so many periods/dots whatever you wanna call them???
Step-by-step explanation:
Hope you have an amazing rest of your day/week!!!
