Multiply 120 x 2.1 o 360 0 252 0 36.0 0 25.2 Please I need this answer fast

A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when

Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, $\bar X = 58.3$

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

$ME = Zc * σ \sqrt{n}$

$ME = 1.96 * 3 \sqrt{25}$

ME = 1.18

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})$

CI = (57.12 , 59.48)

b)

Given data:

mean, $\bar X = 58.3$

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

$ME = zc * σ \sqrt{n}$

$ME = 1.96 * 3\sqrt{100}$

ME = 0.59

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})$

CI = (57.71 , 58.89)

c)

sample mean, $\bar X = 58.3$

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

$ME = Zc * σ \sqrt{n}$

$ME = 2.58 * 3\sqrt{100}$

ME = 0.77

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}$

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

$n \geq (zc *σ/E)^2$

$n = (2.58 * 3/0.5)^2$

n = 239.63

7 0

4 years ago

If the probability of an event happening is

labwork [276]

If the probability of an event is P, the probability of that event NOT happening is equal to 1-P:

Example: if you roll a six-sided dye, what the probability of getting 4.

==> P(4) = 1/6 & the probability of NOT GETTING 4 is P(NOT 4) =5/6
I could have written 1- 1/6 & you'll notice that 1-1/6 =5/6

4 0

4 years ago

What is the quadratic. Formula?

balu736 [363]

Answer:

$x = \frac{ - b ± \sqrt{ {b }^{2} - 4ac } }{2a}$

Step-by-step explanation:

For example, we'll use this quadratic equation.

${x}^{2} + 5x + 6$

To understand how to plug it into the formula we need to know what each term represents.

$a {x}^{2} + bx + c$

So the equation above would be put into the formula like this.

$x = \frac{ - 5± \sqrt{ {5}^{2} - 4(1)(6) } }{2(1)}$

Then we would solve

$\frac{ - 5± \sqrt{25 - 24} }{2} \\ \\ = \frac{ -5±1}{2}$

Now, the equation will branch off into one that solves when addition and one when subtraction.

$\frac{ - 5 + 1}{2} = \frac{ - 4}{2} = - 2 \\ \\ \frac{ - 5 - 1}{2} = \frac{ - 6}{2} = - 3$

So x={-3, -2} (-3 and -2)

6 0

3 years ago

Please answer I need it asap please

stiks02 [169]

Answer:

25.612

Step-by-step explanation:

$\sqrt{20^2+16^2\\}$ = 25.612

5 0

3 years ago

Express the ratio 15 out of 25 as a fraction in simplest form.

Alona [7]

Ok to reduce fractions you have the find the Greatest Common Factor of both the denominator and nominator and factor it out. In this case the GCF for 15 and 25 is 5 so you would divide 15 and 25 by 5 to get 3/5

4 0

4 years ago

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