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tangare [24]
3 years ago
12

Mhanifa can you please help? I will mark brainliest!

Mathematics
1 answer:
Rzqust [24]3 years ago
7 0

Answer:

<u>Given function</u>

  • h(x) = 2x - 1

#15 Find the inverse of h(x)

<u>Substitute x with y and h(x) with x and solve for y:</u>

  • x = 2y - 1
  • 2y = x + 1
  • y = 1/2x + 1/2

<u>The inverse is:</u>

  • h⁻¹(x) = 1/2x + 1/2

#16 The graph with both lines is attached.

The x- and y-intercepts of both functions have reversed values.

#17 Table of the inverse function  will contain same numbers with swapped domain and range.

<u>Initial look is like this:</u>

  • <u>x        |  -3  |  -2  | -1  |  0  |    1  |  2  | 3</u>
  • h⁻¹(x)  |  -1   |       | 0   |      |    1  |      | 2

<u>The rest of the table is filled in by finding the values:</u>

  • <u>x        |  -3  |  -2    | -1  |  0   |  1  |  2   | 3</u>
  • h⁻¹(x)  |  -1   | -0.5 |  0  | 0.5 |  1  | 1.5 | 2

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Value of q is \frac{105}{8} .

<u>Step-by-step explanation:</u>

We have , the equation -2x^2+3=-9x is rewritten in the form of -2(x-p)^2 +q=0 . We need to find What is the value of q . Let's find out:

Let's simplify equation -2x^2+3=-9x into -2(x-p)^2 +q=0 :

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Comparing this equation to -2(x-p)^2 +q=0 , q =\frac{105}{8} .

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