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grandymaker [24]
2 years ago
5

Ordered pair solution to y > 3

Mathematics
1 answer:
nika2105 [10]2 years ago
7 0

Answer:what I don’t get it pls explain

Step-by-step explanation:

Umm pls explain well is there supposed to be a picture or something

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If you divide 4,296 by 6 it would equal 716.

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Which expression is equivalent to<br> 0 +<br> 2<br> 29<br> C+3<br> C+2<br> C+3<br> C+2
Kryger [21]

Answer:

C+3

Step-by-step explanation:

6 0
2 years ago
a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

8 0
3 years ago
Whats 6 X 1 X + 5 X 1/10 in standard form and someone pls
Galina-37 [17]
The standard form of 6x1x5x1/10 =3 x 10 ^0, any number raised to the power of 0 is 1 so 1 x 3 = 3
3 0
2 years ago
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