Ok so
t=number of text messsages
p=number of picture messages
total number is 33
t+p=33
if text is 0.18 per pic and picture is 0.45 per text
total cost is 8.3
0.18t+0.45p=8.3
times 100 both sides for ease
18t+45p=830
we now have 2 equations
t+p=33
18t+45p=830
multiply first equation by -18 and add to second equation
18t+45p=830
<span>-18t-18p=-594 +</span>
0t+27p=236
27p=236
divide both sides by 27
p=8.740740740740744
this is impossible becasue you can't send 0.740740740740744 of a message so you did a mistype somewhere
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
Answer:
50 = p + 42
Step-by-step explanation:
The unknown part of this equation is the variable p, the number of people that left. So you want to add p to 42 and that will give you the total number of football players, which is 50. In order to get p, you need to get it by itself and make it equal something. Subtract 42 from both sides and you are stuck with 50-42 = p
p = 8
Answer:
A 35°
Step-by-step explanation:
180°-110°=70°
180°-70°-75°=35°
Answer:
D) 3x
Step-by-step explanation:
The difference of adjacent terms is ...
(-7x) -(-10x) = (-7+10)x = 3x . . . . the common difference
