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2 years ago

Which is the constant term of the algebraic expression -2x2 + 17 -15x + 7xy? -15 -2 7 17

Mathematics

2 answers:

Kobotan [32]2 years ago

8 0

Answer:

4th Option is correct that is constant term is given expression is 17.

Step-by-step explanation:

Given Algebraic Expression = $-2x^2+17-15x+7xy$

We need to find Constant term in the given algebraic expression.

We know that Constant term in the Expression are term which has only numbers not a variable.

So, In given expression $-2x^2\:,\:-15x\:and\:7xy$ are not constant terms as all terms has variables.

Only 17 is constant term.

Therefore, 4th Option is correct that is constant term is given expression is 17.

const2013 [10]2 years ago

4 0

17. The constant is the number that's by itself with no variable attached to it. Hope this helped!

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A boat goes 3/4 hours with a speed of 8mph and 1/3 hours with a speed of 12mph. What distance did the boat cover in all this tim

Ludmilka [50]

Answer:

<em>10 miles</em>

Step-by-step explanation:

Distance d = v t

v - speed/velocity

t - time

<em>d</em> = $\frac{3}{4}$ (8) + $\frac{1}{3}$ (12) = 6 + 4 = <em>10 miles</em>

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2 years ago

Find the area and perimeter.

yan [13]

Answer:

Area = 33√3

Perimeter = 122

Step-by-step explanation:

This is a parallelogram and perimeter for a parallelogram is calculated by adding side length to base and that's multiplied by 2

perimeter (6 + 11) × 2 = 122

The area is calculated by multiplying height to the base

there's a 30° 60° 90° special triangle inside the parallelogram and the side length that sees 60° in this special triangle is 3√3 so this is our height and base is given as 11

Therefore the area of this parallelogram is

3√3 × 11 = 33√3

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2 years ago

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Setler79 [48]

The answer for the question is 2:5

8 0

2 years ago

Multiply.

Nady [450]

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Explanation:</h2>

Here we have the following expression:

$3\sqrt{22}\sqrt{58}\sqrt{18}$

So we need to simplify that radical expression. By property of radicals we know that:

$\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}$

So:

$3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}$

The prime factorization of 22968 is:

$22968=2^3\cdot 3^2\cdot11\cdot 29$

Hence:

$3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}$

By property:

$\sqrt[n]{a^n}=a$

So:

$3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}$

Finally:

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

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3 years ago

Three consecutive integers sum to 6. What is the least of these integers?

dexar [7]

Answer:

The least of the three integers is 1.

Step-by-step explanation:

Hi there!

Let <em>x</em> be equal to the least of these integers.

Let <em>x</em>+1 and <em>x</em>+2 be the next consecutive integers.

We're given that these integers have a sum os 6.

We can use these to construct an equation:

$(x)+(x+1)+(x+2)=6$

Combine like terms:

$x+x+1+x+2=6\\x+x+x+1+2=6\\3x+3=6\\3x=3\\x=1$

Therefore, the least of these integers is 1.

The other two integers would be 2 and 3.

I hope this helps!

3 0

2 years ago