Find all the real zeros of x3-2x2-5x+6=0.
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
y = -1/3x + 2
m1 = -1/3
Slope of the perpendicular line = -1/m1 = -1 ÷ =
Equation of the required line : y = mx +b
y = 3x + b
Plugin x = 2 and y 10 in the above equation
10 = 3*2+ b
10 = 6 +b
10 - 6 = b
b = 4
Equation: y = 3x + 4
We can find a formula for nth term of the given sequence as follows:
1, 5, 12, 22, 35
The 1st differences between terms:
4, 7, 10, 13
The 2nd differences :
3, 3, 3
Since it takes two rounds of differences to arrive at a constant difference between terms, the nth term will be a 2nd degree polynomial of the form: , where c is a constant. The coefficients a, b, and the constant c can be found.
We can form the following 3 equations with 3 unknowns a, b, c:
Solving for a, b, c, we get:
a = 3/2, b = -1/2, c = 0
Therefore, the nth term of the given sequence is: