You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.
I’m pretty sure This rounds to 900
Answer:
C) 17
Step-by-step explanation:
Using the rule
A^2 + B^2 = C^2
8^2 + 15^2 = x^2
64 + 225 = x^2
x^2 = 289
x= _/-289
x = 17
Answer:
<h2>12</h2>
Step-by-step explanation:
To evaluate 4P2, we will use the permutation formula as shown;
nPr = 
4P2 = 
4P2 = 12
Answer:
since we can't see the image, I'm just giving it a try
if it's wrong, it's fine for you to delete it
(see below)
Step-by-step explanation:
if one of the length is 5.6 units then the other will be 5 units
if one of the length is 4 units then the other will be 7 units
if one of the length is 2 units then the other will be 14 units
if one of the length is 1.86666666667 units then the other will be 15 units
if you're looking of an area, it might be 7 units
and I think that's all I've got
(hope it helps)
