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3 years ago

PLZ HELPI DON'T UNDERSTAND THIS ONE.

Mathematics

2 answers:

seraphim [82]3 years ago

7 0

Answer:

$50 to produce each and $150 would be her income

Step-by-step explanation:

Nastasia [14]3 years ago

5 0

Answer:

250 dollars

Step-by-step explanation:

5x50

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Evaluate 7P4 Evaluate 12C5

Verdich [7]

Answer:

Below.

Step-by-step explanation:

7P4

= 7! / (7-4)!

= 7*6*5*4*3*2*1 / ( 3*2*1)

= 7*6*5*4

= 840.

12C5

= 12! / (12-5)! 5!

= 12*11*10*9*8*7*6*5*4*3*2*1 / ( 7*6*5*4*3*2*1 * 5*4*3*2*1)

= 12*11*10*9*8 / 5*4*3*2*1

= 792.

5 0

3 years ago

Which Pairs are additive inverses? a. 6,-(-6) b. -7,7 c.-7,-7 d.7,7 e.6,-6

xz_007 [3.2K]

I was never sure of what the "additive inverse" is.
So, just now, just for you, I went and looked it up.

The additive inverse of any number ' A ' is the number
that you need to ADD to A to get zero. That's all !

So now, let's check out the choices:

a), 6, -(-6)

That second number, -(-6), is the same as +6 .
So the two numbers are the same.
Do you get zero when you add them up ? No.

b). -7, 7
What do you get when you add -7 and 7 ?
You get zero.
So these ARE additive inverses.

c). -7, -7
What do you get when you add -7 to -7 ?
You get -14 . That's not zero, so these
are NOT additive inverses.

d). 7, 7
What do you get when you add 7 to 7 ?
You get 14. That's NOT zero, so these
are NOT additive inverses.

e). 6, -6
What do you get when you add 6 to -6 ?
You get zero.
So these ARE additive inverses.

What do we end up with from the list of choices:

a)., c)., and d). are NOT additive inverses.

b). and e). ARE additive inverses.

7 0

3 years ago

Read 2 more answers

The length of a rectangle is three times its width. The perimeter of the rectangle is at most 112cm. Which inequality models the

miss Akunina [59]

Answer: w ≤ 14 cm , L ≤ 42 cm

Step-by-step explanation:

width (w): w

Length(L): 3w

Perimeter (P) = 2w + 2L

P ≤ 112

2w + 2L ≤ 112

2(w) + 2(3w) ≤ 112

2w + 6w ≤ 112

8w ≤ 112

w ≤ 14

8 0

3 years ago

HELP ME PLEASE Again lol

KatRina [158]

False
true
false
i could be wrong but i’m 85% certain

4 0

3 years ago

First you to find the worksheet and download it plase I need help

Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = $3^{x + 2}$

The asymptote is given as x → -∞, f(x) = $3^{x + 2}$ → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = $3^{0 + 2}$ = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = $5^{1 - x}$

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = $5^{1 - 0}$ = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = $2^{x + 3}$ - 1

The asymptote is $2^{x + 3}$ → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) = $2^{0 + 3}$ - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, $2^{x + 3}$ - 1 = 0

$2^{x + 3}$ = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) $f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2$

The asymptote is $\left (\dfrac{1}{2} \right)^{x - 2}$ → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = $f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6$

The y-intercept is (0, 6)

7 0

3 years ago