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2 years ago

Which of the forms below is a pyramid?

Mathematics

2 answers:

Arlecino [84]2 years ago

5 0

Answer: A
B is a Triangular Prism, then C and D is just self explanatory

gizmo_the_mogwai [7]2 years ago

4 0

Answer:

Step-by-step explanation:

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The expression 5n+2 can be used to find the total cost in dollars of bowling where n us is the number of games bowled and 2 repr

sukhopar [10]

Plug in the known variables.

5n + 2 n = number of games bowled

5(3) + 2 = 15 + 2 = 17

8 0

2 years ago

What is the inequality shown?

Lady bird [3.3K]

It shows the interval

[-2,8) or -2≤x<8

7 0

1 year ago

How many 1/4 - pound packages of cheese can the deli make with 12 - pound of cheese? Please help !!!

devlian [24]

Answer:

48 packages

Step-by-step explanation:

recipicate 1/4 which is 4 the multiply by 12

Hope this helps!!!

6 0

2 years ago

Read 2 more answers

If a Customer places an order for $47.36 and it’s late, then how much would the customer be refunded if the refund is 20% on the

Serggg [28]

$9.47

I just multiplied the total by the refund percentage to get that number. It’s just like finding a tip.

6 0

2 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

2 years ago