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Lana71 [14]
4 years ago
8

If the check after the substitution of the answer doesn't work, does that mean that the result is incorrect for equation with va

riables on both sides
Mathematics
1 answer:
Alecsey [184]4 years ago
8 0
I don't understand what your point is. Mind posting a picture or something?
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Can you help me please?? I don't understand.
katen-ka-za [31]

 Answer: I think it is d because the domain is the x and the range  is the y  Hope this help :)

Step-by-step explanation:

8 0
3 years ago
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Please help me with this question !!
ad-work [718]

9514 1404 393

Answer:

  E

Step-by-step explanation:

A. The ⊥ symbol means "is perpendicular to". The two lines l1 and l2 are parallel, not perpendicular.

B. Angles g and f are vertical angles. They are congruent. If both are 45°, then they are complementary, but we cannot assume that is the case. They are shown as obtuse angles.

C. Angles e and h are vertical angles. They are congruent. If both are 45°, then they are complementary, but we cannot assume that is the case. They are shown as acute angles, but with no particular angle measure.

D. Angle d is shown as an acute angle. In general, we cannot assume its measure based on its appearance in the diagram.

E. Angles d and g are shown as, respectively, an acute angle and an obtuse angle. Where a transversal crosses parallel lines, all acute angles are supplementary to all obtuse angles. Hence the sum of angles d and g will be 180 degrees. This statement is true.

F. Angles c and f are congruent angles, shown as obtuse. Their sum will be 270° if and only if their measures are each 135°. There is no indication in the diagram that the angles have any particular measure, so we cannot assume their sum is 270°.

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3 years ago
An edge on a polyhedron is the intersection of three or more faces.<br><br> True<br><br> False
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This statement is true.
7 0
4 years ago
Solving simultaneous equations with one quadratic, x^2+y^2=16 and y=x+3
Svetlanka [38]
If y=x+3, then in the first equation you have

x^2+(x+3)^2=x^2+(x^2+6x+9)=2x^2+6x+9=16

Rewriting a bit, you get

x^2+3x+\dfrac92=8

x^2+3x+\dfrac94+\dfrac94=8

\left(x+\dfrac32\right)^2=\dfrac{23}4

x=-\dfrac32\pm\dfrac{\sqrt{23}}2

Now, since y=x+3, you also get

y=-\dfrac32\pm\dfrac{\sqrt{23}}2+3=\dfrac32\pm\dfrac{\sqrt{23}}2

So, there are two solutions here:

(x,y)=\left(-\dfrac32+\dfrac{\sqrt{23}}2,\dfrac32+\dfrac{\sqrt{23}}2\right)
(x,y)=\left(-\dfrac32-\dfrac{\sqrt{23}}2,\dfrac32-\dfrac{\sqrt{23}}2\right)
7 0
3 years ago
Please tell me where to graph this!! (include if i open circle or not please) (NO FILE ANSWER!!!)
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Answer:

1.Make the circle open

2.put the dot on 5

3. change direction

Step-by-step explanation:

A solid dot on a number line graph indicates that the given number should be included as a possible solution, whereas an open dot indicates that the given number cannot be a solution. For example, if you graph x > 7, you place an open dot at 7.

Have a nice day! :-)

7 0
3 years ago
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