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1 year ago

Express each of the following fractions as a percentage 9 by 27

Mathematics

2 answers:

valentina_108 [34]1 year ago

5 0

Answer:

9/27 = 33.3% (rounded to the nearest tenth)

Step-by-step explanation:

Let, x equal the percent out of 100

Step 1: Cross multiply

1. 9/27 ∙ x/100

2. 900 = 27x

Step 2: Divide both sides by 27

1. 900/27 = 27x/27

2. 33.333333%... = x

3. Hence, the answer is 33.3% (rounded to the nearest tenth)

Over [174]1 year ago

4 0

Answer:

9/27 = 1/3 and if we convert it into decimal it equal to

(Decimal: 0.333333)

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Amiraneli [1.4K]

So one easy way is
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$\frac{18x-42}{5}$ =6t

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2 years ago

If a line contains the point (0, -1) and has a slope if 2, then which if the following points also lies on the line? (2, 1), (1,

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2 years ago

Mr. Williams is driving on a highway at an average speed of 50 miles per hour. His destination is 100 miles away. The

svetlana [45]

Answer:

t = -d/50 + 2

0.5 hour

Step-by-step explanation:

Given the equation:

d = 50 - 100t

The inverse function:

A.) solving for t

d = 100 - 50t

d - 100 = - 50t

Divide both sides by - 50

d/-50 - (100/-50) = - 50t/-50

-d/50 - (-2) = t

t = -d/50 + 2

B) using the inverse function:

t = -d/50 + 2

Miles driven (d) = 75, find time (t)

t = - 75/50 + 2

t = - 1.5 + 2

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4 0

2 years ago

Help pls! Giving brainliest!!!!!

RUDIKE [14]

Answer:

$27 = 3 \times 3 \times 3\\\\\frac{1}{27} = \frac{1}{3 \times 3 \times 3} = \frac{1}{3^{3}} = 3^{-3}$

option 3

3 0

2 years ago

| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the

Westkost [7]

Answer:

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

Left Speed(km/h) Time

Car: 12PM X

Van: 12PM 60

Car/Van

DistanceCar AB + z

DistanceVan Az

Ratio: (AB+z)/Az = 7/5

Time until both meet = T (in hours)

Distance Car: xT

Distance Van: 60T

====

xT = AB + z

60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is: time (hr) = 108 km/(84 km/h)

time = 1.286 hours

Distance for at 1.289 hours is: distance (km) = (60 km/h)*(1.286 h)

distance = 77.14 km

At 1.286 hours, the car reverses direction. The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours. The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let t be the time after 1.286 hours that both vehicles meet/collide.

t*(60 km/h) + t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

==============

CHECK

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

YES

3 0

2 years ago

Express each of the following fractions as a percentage 9 by 27 ​

Express each of the following fractions as a percentage 9 by 27