The digits 2, 4, and 6 can be arranged to form six different three-
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Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by
where
Here we're given
p=0.10 [ success = defective ]
n=3
(a) x=0
(b) x=2
(c) x ≥ 2
Here we're given
p=0.10 [ success = defective ]
n=3
(a) x=0
(b) x=2
(c) x ≥ 2