Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
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1/r = (3 1/2)/245
(3 1/2)r = 245
r = 245/3 1/2
r = 70
scale is 1 in to 70 miles.
Answer:
c.....c......c
Step-by-step explanation:
1292 this shows how many people are on the team and also how many different rotations can be allowed