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inysia [295]
2 years ago
13

The ratio of the areas of the two squares is 25 to 9. The side length of the smaller square is 30 meters. How long is the side l

ength of the larger square? Explain your reasoning
Mathematics
1 answer:
Ratling [72]2 years ago
6 0
Ratios of Area of the two squares = 25:9
So then let the areas be A1 = 25A and A2 = 9A, A is common element
Side of the smaller area S2 = 30 meters
Area of the smaller square A2 = 30 x 30 = 900
We have area of smaller square as 9A = 900 => A = 100
Area of the large square = 25A = 25 x 100 = 2500.
Hence S1^2 = 2500 => S1 = 50 meters which is 20 meters longer than the
side of the smaller square.
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3 years ago
When graphed, which function has a horizontal asymptote at 4?
galben [10]

Answer:

<em>Correct answer: C. f(x) = 2(3)x + 4</em>

<u><em>(please note we changed the expression of the function to exponential form which we believe is the correct form of the question)</em></u>

Step-by-step explanation:

<u>Horizontal Asymptote</u>

The graph of a function is said to have a horizontal asymptote at y=a if one or both the following limits exist

\lim\limits_{x \rightarrow \infty}f(x)=a

\lim\limits_{x \rightarrow -\infty}f(x)=a

The horizontal asymptotes are horizontal lines to which the function tends when x increases or decreases without limits.

Let's analyze each one of the options provided:

A.  f(x) = 2x -4

\lim\limits_{x \rightarrow \infty}(2x-4)=+\infty

\lim\limits_{x \rightarrow -\infty}(2x-4)=-\infty

No horizontal asymptote

B.  f(x) = -3x + 4

\lim\limits_{x \rightarrow \infty}(-3x+4)=-\infty

\lim\limits_{x \rightarrow -\infty}(-3x+4)=\infty

No horizontal asymptote

C. f(x) = 2\cdot 3^x + 4

\lim\limits_{x \rightarrow \infty}(2\cdot 3^x + 4)=2\cdot 3^\infty + 4=\infty

\lim\limits_{x \rightarrow \infty}(2\cdot 3^x + 4)=2\cdot 3^{-\infty} + 4=0+4=4

This function has a horizontal asymptote at y=4

D. 3\cdot 2^x -4

\lim\limits_{x \rightarrow \infty}(3\cdot 2^x - 4)=3\cdot 2^\infty - 4=\infty

\lim\limits_{x \rightarrow \infty}(3\cdot 2^x- 4)=3\cdot 2^{-\infty} - 4=0-4=-4

This function has a horizontal asymptote at y=-4

Correct answer: C.

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Answer:

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Step-by-step explanation:

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