This problem can be solved through simple arithmetic
progression
Let
a1 = the first term of the sequence
a(n) = the nth term of the sequence
n = number of terms
d = common difference
Sn = sum of all terms
given
a1 = 12
a2 = 16
n = 10
d = 16 -12 = 4
@n = 10
a(n) = a1 + (n-1)d
a(10) = 12 + (9)4
a(10) = 48 seats
Sn = (n/2) * (a1 + a(10))
Sn = 5* (12 + 48)
Sn = 300 seats
Therefore the total number of seats is 300.
It is 10 times greater because
10x10=100
Answer: D).-20
Step-by-step explanation:
Answer:
0.5x7
Step-by-step explanation:
Assuming that the original expression is 
, according to PEMDAS multiplication takes priority over addition and subtraction,, and therefore, from the choices given, 0.5 * 7 must be performed first.
Answer: a= b/ b+2
Step 1: factor out variable a.
a(b+2)= b
Step 2: divide both sides by b+2.
a(b+2)/ b+2 = b/b+2
