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3 years ago

Answer=== -5process???

Mathematics

2 answers:

natali 33 [55]3 years ago

7 0

Answer:

x = -5 (process below)

Step-by-step explanation:

1) To solve this easily, you can cross multiply. Multiply the numerator of the first fraction with the denominator of the second fraction, and multiply the denominator of the first fraction with the numerator of the second fraction:

$\frac{2}{3x+1} = \frac{1}{2x+3} \\2(2x +3) = 1(3x + 1)\\4x + 6 = 3x + 1$

2) Next, isolate x to find its values. Subtract both sides by 3x.

$4x + 6 = 3x +1\\x + 6 = 1$

3) Finally, subtract both sides by 6.

$x + 6 = 1 \\x = -5$

SSSSS [86.1K]3 years ago

4 0

Answer:

x=-5

Step-by-step explanation:

First, you have to cross multiply.

2*2x+3 1*3x+1

4x+6=3x+1

Then, you subtract 3x from both sides.

4x+6=3x+1

-3x -3x

x+6=1

Next, you subtract 6 from both sides.

x+6=1

-6 -6

x=-5

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3 years ago

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noname [10]

Answer:

$x=\dfrac{3+ \sqrt{29}}{2}, \quad \dfrac{3- \sqrt{29}}{2}$

Step-by-step explanation:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Given quadratic equation:

$x^2-3x-5=0$

Define the variables:

$\implies a=1, \quad b=-3, \quad c=-5$

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(1)(-5)}}{2(1)}$

$\implies x=\dfrac{3 \pm \sqrt{9+20}}{2}$

$\implies x=\dfrac{3 \pm \sqrt{29}}{2}$

Therefore, the exact solutions to the given quadratic equation are:

$x=\dfrac{3+ \sqrt{29}}{2}, \quad \dfrac{3- \sqrt{29}}{2}$

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2 years ago

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If (a+b)^2=54, and (a-b)^=46, then a^2+b^2=?

erastovalidia [21]

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2 years ago

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Answer:

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Step-by-step explanation:

The point-slope form of the equation for a line is ...

y -k = m(x -h) . . . . . . for slope m and point (h, k)

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3 years ago

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masha68 [24]

Answer:

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Step-by-step explanation:

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Answer=== -5process???​

Answer=== -5process???