An=-31+(n-1)-11 find the eleventh term
a11 = -31 + (-11) (11-1)
a11 = -31 +-11(10)
a11 =-31 +-110
a11 = -142
Answer:
area of the figure: 29.92 m²
formula's:
- area of rectangle: length * width
- area of sector: ∅/360 * πr²
solving steps:
area of rectangle + area of sector
5.5 * 4 + 30/360 * π(5.5)²
22 + 7.919
29.92 m²
Hello!
hint: we can rewrite your function as below:
<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π =
=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)
</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
<span>"4P=π"
Hope this Helps! Have A Wonderful Day! :)</span>
Answer:
Alli khanaw .................
Step-by-step explanation:
volume of cylinder =π r²h
= 3.14 × 17×17×16
= 14519.31 inches square .
plz mark my answer as brainlist if you find it useful
