The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find
1 answer:
Answer: C.-1.5
Step-by-step explanation:
Given: The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation
of 20 hours.
Let X be a random variable that represent the burning time of a very large candle.
Formula:
For X = 2470
So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5
Hence, the correct option is C.-1.5.
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Answer:
Option a :
Step-by-step explanation:
Given :
The drama club sold 100 tickets to a show, it had $300 in profit.
The next show, it had sold a total of 200 tickets and had a total of $700 profit.
To Find : Equation models the total profit, y, based on the number of tickets sold, x
Solution :
For 100 tickets he had $300 in profit .
⇒ ()=(100,300)
For 200 tickets he had $700 in profit .
⇒ ()=(200,700)
We will use point slope form i.e.
--(A)
Now, to calculate m we will use slope formula :
Now, putting values in (A)
Thus Option a is correct i.e.
9514 1404 393
Answer:
x = 8/7
Step-by-step explanation:
.2(.7x-5)+0.2=1.4(x-1.6) . . . . given
Eliminating parentheses, we have ...
0.14x -1 +0.2 = 1.4x -2.24
1.44 = 1.26x . . . . . . . add 2.24-0.14x to both sides
x = 1.44/1.26 . . . . . . divide by the coefficient of x
x = 8/7 . . . . . . . . . . .simplify the fraction
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As a repeating decimal, the value of x is ...
However, the notation 1.(142857) is usually reserved for the case where the contents of parentheses are being multiplied by the factor in front. You would need to consult your instructions to see how the decimal version of the answer should be entered. (Quite often, rounding is suggested.)
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<em>Additional comment</em>
The equation in the text of your question is different from the one in the picture. We have answered for the one in the picture. The text asks for the solution of a quadratic. Those two solutions are approximately 1.085 and 16.057.