Pretty lost not too sure what to do

9966 [12]

Firstly I would revert these back to improper fractions:

So 17/6 ÷ 24/5

Then I would use keep, change, flip

So 17/6 * 5/24

Finally simplify

85/144

Final Answer: 85/144

3 0

3 years ago

If a plane intersects a sphere, what is the shape of the resulting cross section?

lana66690 [7]

A circle is the answer

6 0

3 years ago

Read 2 more answers

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago

Please help!<br><br> If sin(xº)=cos(yº) find k if x=2k+3 and y=6k+7

USPshnik [31]

answer

10

step-by-step explanation

the equation given is sin(x) = cos(y) with x = 2k + 3 and y = 6k + 7

substitute in 2k+ 3 for x in sin(x) and substitute in 6k + 7 for y in cos(y)

sin(x) = cos(y)

sin(2k + 3) = cos(6k + 7)

we know that sin(x) = cos(90 -x)

sin(2k + 3)

= cos(90 - (2k + 3) )

= cos(90 - 2k - 3)

= cos(87 - 2k)

substitute this into the equation sin(2k + 3) = cos(6k + 7)

sin(2k + 3) = cos(6k + 7)

cos(87 - 2k) = cos(6k + 7)

87 - 2k = 6k +7

80 = 8k

k = 10

7 0

3 years ago

What is the slope of the line with the equation -7x + 4y = -8

lys-0071 [83]

Answer:

1 3/4 or 7/4 or 1.75

Step-by-step explanation:

4 0

3 years ago