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stiks02 [169]
3 years ago
13

Simplify the expression: w2 + 7w2 + 8w - 5 + 9 - 2w2

Mathematics
1 answer:
ololo11 [35]3 years ago
4 0
<h3>6w^2 +8w +4 is the simplified expression</h3>

<em><u>Solution:</u></em>

Given that,

We have to simplify

w^2 + 7w^2 + 8w -5+9-2w^2

We can simplify the above expression by combining the like terms

Like terms are terms that has same variable with same exponent and same or different coefficient

From given,

w^2 + 7w^2 + 8w -5+9-2w^2

Group the like terms

w^2 + 7w^2 -2w^2 + 8w - 5+9\\\\Combine\ the\ like\ terms\\\\6w^2 +8w -5+9\\\\Combine\ the\ constants\\\\6w^2 +8w +4

Thus the given expression is simplified

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The base of an isosceles triangle is 2 cm. The perimeter of the triangle is 10 cm.
cluponka [151]

Answer and Step-by-step explanation:

Greetings!

Let's~solve~your~question!

To~find~the~length~of~equal~sides~of~an~isosceles~triangle,~we~use~the~following\\formula.

\boxed{~P=2a+b~}

Now,~solving~for~``a":

P=\frac{P}{2} -\frac{b}{2}

=\frac{10}{2}-\frac{2}{2}

=5-1

=4

Thus,~each~equal~sides~of~an~isosceles~triangle~is~4cm.

Hope~my~answer~helps~and~have~a~blessed~day~ahead!

-Isabelle~Williams

8 0
3 years ago
How do I simplify this expression<br> 3(4+3r)
vivado [14]
3(4+3r)
= 12 + 9r

Hope it helped :)
5 0
3 years ago
Read 2 more answers
There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one
diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0
4 years ago
What is 44 divided by 93
Shalnov [3]

Answer:

0.47311827957

Step-by-step explanation:

44/93= 0.47311827957

hope this helps u

5 0
3 years ago
What's the slope and y-intercept of the equation y = 9? Question 3 options: A) m = 0; b = -9 B) m = 0; b = 0 C) m = 0; b = 9 D)
erastovalidia [21]

Answer:

b

tep-by-step explanation:

8 0
3 years ago
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