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Mazyrski [523]
3 years ago
5

A density curve for all the possible temperatures between 0 degrees F and 40 degrees F is a rectangle. What is the height of the

rectangle in this density curve?
A. 0.025
B. 0.00025
C. 0.0025
D. 0.25
Mathematics
2 answers:
Yuki888 [10]3 years ago
8 0

Answer:

0.25

Step-by-step explanation:

took quiz :)

Eddi Din [679]3 years ago
3 0

Answer:

Concept: Higher Level Mathematics

  1. You have a density curve, aka probability
  2. You are asked to find the height
  3. Hence 0-40F has 40 total integers or values of X(probability)
  4. Hence you have a total Area of
  5. \binom{40}{0}
  6. Integrate f(x) to get 0.025.
  7. Hence the answer is A
  8. Rate positively and give brainlist

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Answer:

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057  

p_v =P(Z>0.0057)=0.4977  

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Step-by-step explanation:

1) Data given and notation  

X_{M}=23 represent the number of men that said they enjoyed the activity of Saturday afternoon shopping

X_{W}=8 represent the number of women that said they enjoyed the activity of Saturday afternoon shopping

n_{M}=66 sample of male selected

n_{W}=23 sample of demale selected

p_{M}=\frac{23}{66}=0.34848 represent the proportion of men that said they enjoyed the activity of Saturday afternoon shopping

p_{W}=\frac{8}{23}=0.34782 represent the proportion of women with red/green color blindness  

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment , the system of hypothesis would be:  

Null hypothesis:p_{M} \leq p_{W}  

Alternative hypothesis:p_{M} > p_{W}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

Where \hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{23+8}{66+23}=0.34831

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Replacing in formula (1) the values obtained we got this:  

z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057  

4) Statistical decision

Using the significance level provided \alpha=0.05, the next step would be calculate the p value for this test.  

Since is a one side right tail test the p value would be:  

p_v =P(Z>0.0057)=0.4977  

So the p value is a very high value and using the significance level \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.  

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Step-by-step explain

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A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.

For the given function, there is no horizontal asymptote.

We can find the slant asymptote by using long division:

(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))

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