Total coins = 10 ( 4 + 3 + 3 = 10).
The probability of picking a nickel first = 4/10 = 2/5 ( 4 nickels out of 10 total).
The probability of picking a dime second = 3/9 = 1/3 ( 3 dimes out of 9 coins left).
The probability of picking the third coin as a quarter = 3/8 ( 3 quarters out of 8 coins left).
The probability of picking all three in that order = 2/5 x 1/3 x 3/8 = 1/20
Hello!
First, let's write the problem.

Subtract 10 from both sides.


Divide both sides by 9.


When we got absolute value, we are going to get two results.

and

Let's solve the first one,

Subtract 8 from both sides.


Let's solve the second one.

Subtract 8 from both sides.


Let's combine the ranges.

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!
- TetraFish
We know that
<span>the Consumer Price Index
(CPI) is equals to
</span>CPI=100*[cost of the pizza today/cost of the pizza <span>in the base year]
[</span>cost of the pizza in the base year]=100*[cost of the pizza today/CPI]
cost of the pizza today=$12
<span>CPI=200
so
</span>[cost of the pizza in the base year]=100*[12/200]-----> $6
<span>
the answer is
</span>The cost of the pizza in the base year is $6<span>
</span>