Question

What is angle a? ive already gotten the other side

Answer 1

Answer:

$m\angle A=\tan^{-1}(\frac{m}{n})$

$AB=\sqrt{m^2+n^2}$

Step-by-step explanation:

Given:

In Δ ABC

m∠C= 90°

$BC=m$

$AC=n$

For the triangle ABC we can apply trigonometric ratio to find m∠A.

We have:

$\tan\angle A=\frac{BC}{AC}$

Substituting values of side BC and AC

$\tan \angle A=\frac{m}{n}$

Taking inverse tan to get m∠A.

∴ $m\angle A=\tan^{-1}(\frac{m}{n})$

AB can be found out using Pythagorean theorem:

AB being the hypotenuse can be written as

$AB^2=BC^2+AC^2$

Substituting values of side BC and AC

$AB^2=m^2+n^2$

Taking square roots both sides:

$\sqrt{AB^2}=\sqrt{m^2+n^2}$

∴ $AB=\sqrt{m^2+n^2}$