Answer:
The pounds of mulch the store sells are 108 and the pounds of gravel the store sells are 72.
Step-by-step explanation:
Let
x -----> pounds of mulch the store sells
y ----> pounds of gravel the store sells
we know that
-----> equation A
Remember that
![2\frac{1}{4}\ lb=\frac{2*4+1}{4}=\frac{9}{4}\ lb](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B4%7D%5C%20lb%3D%5Cfrac%7B2%2A4%2B1%7D%7B4%7D%3D%5Cfrac%7B9%7D%7B4%7D%5C%20lb)
![1\frac{1}{2}\ lb=\frac{1*2+1}{2}=\frac{3}{2}\ lb](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B2%7D%5C%20lb%3D%5Cfrac%7B1%2A2%2B1%7D%7B2%7D%3D%5Cfrac%7B3%7D%7B2%7D%5C%20lb)
so
![\frac{x}{y}=\frac{(9/4)}{(3/2)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D%5Cfrac%7B%289%2F4%29%7D%7B%283%2F2%29%7D)
![\frac{x}{y}=\frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D%5Cfrac%7B3%7D%7B2%7D)
-----> equation B
solve the system by substitution
substitute equation B in equation A
![\frac{3}{2}y+y=180](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7Dy%2By%3D180)
solve for y
![\frac{5}{2}y=180](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7Dy%3D180)
![y=180(2)/5\\y=72](https://tex.z-dn.net/?f=y%3D180%282%29%2F5%5C%5Cy%3D72)
Find the value of x
The solution is the ordered pair (108,72)
therefore
The pounds of mulch the store sells are 108 and the pounds of gravel the store sells are 72.
Answer:
Step-by-step explanation:
DB should equal CB plus DC.
First write an expression to represent DC.
(x+168)-(3x+134)
x+168-3x-134
-2x+34
Then write an equal for DC plus CB equals DB
-2x+34+71= 153+2x
-2x+105= 153+2x
-4x+105=153
-4x=48
x= -12
Now plug in the value of x to find DB
153+2(-12)
153-24
129
Final answer: 129
Answer: 22.2, 22,200
Step-by-step explanation: I believe that the comma was supposed to be a decimal, if so the first one is your answer, if its supposed to be a comma, is is the second one.