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artcher [175]
3 years ago
15

Una carretera recta tiene un ángulo de elevación de 3 grados respecto al plano horizontal. ¿Qué distancia hay que recorrer para

alcanzar una elevación de 30 metros sobre la horizontal?
Mathematics
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

572.4 m

Step-by-step explanation:

Fórmula del ángulo de elevación =

tan θ = Opuesto / Adyacente

θ = 3 °

Opuesto = 30 m

Adyacente =?

Por eso

bronceado 3 = 30 m / x

Multiplicar cruzada

bronceado 3 × x = 30 m

x = 30 m / bronceado 3

x = 572.43410063m

Aproximadamente = 572.4 m

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Answer: c - 6 = 20

Explanation:

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Answer:

1/2 1/4 1/6 1/8 1/10 1/12 1/14 1/16 1/18 1/20 etc...

Step-by-step explanation:

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Suppose a triangle has two sides of length 3 and 4 and that the angle between these two sides is 60 degrees . What is the length
Darya [45]

Answer:

  √13 ≈ 3.6056

Step-by-step explanation:

The Law of Cosines can be used to figure this. If the third side is "c", then it tells you ...

  c² = a² + b² - 2ab·cos(C)

  c² = 3² + 4² -2(3)(4)(cos(60°)) = 9 + 16 - 24(1/2) = 13

  c = √13 ≈ 3.6056

The length of the third side is √13, about 3.6056.

5 0
3 years ago
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san4es73 [151]

Answer:

Its either answer B. or D. Sorry if I'm wrong and I hope this sorta helps.

7 0
3 years ago
Please answer this question now
lidiya [134]

Answer:

C = (2,2)

Step-by-step explanation:

B = (10 ; 2)

M = (6 ; 2)

C = (x ; y )

|___________|___________|

B (10;2)            M (6;2)             C ( x; y)

So:

dBM = dMC

√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]

(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2

0 + (-4)^2 = (y-2)^2 + (x - 6)^2

16 = (y-2)^2 + (x - 6)^2

16 - (x - 6)^2 = (y-2)^2

Also:

2*dBM = dBC

2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]

4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2

4*(16) = (y-2)^2 + (x - 10)^2

64 = (y-2)^2 + (x - 10)^2

64 = 16 - (x - 6)^2 + (x - 10)^2

48 = (x - 10)^2 - (x - 6)^2

48 = x^2 - 20*x + 100 - x^2 + 12*x - 36

48 = - 20*x + 100 + 12*x - 36

8*x = 16

x = 2

Thus:

16 - (x - 6)^2 = (y-2)^2

16 - (2 - 6)^2 = (y-2)^2

16 - (-4)^2 = (y-2)^2

16 - 16 = (y-2)^2

0 =  (y-2)^2

0 = y - 2

2 = y

⇒ C = (2,2)

4 0
3 years ago
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