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vodomira [7]
3 years ago
13

Rita filled 2/5 of a jug with fruit juice. She then added 200 ml of milk to make a milkshake. At this stage, the ratio of the fr

uit juice to milk is 3:2
how much more liquid can the jug hold?
a)250 ml
b)300 ml
c)400 ml
d)450 ml
Mathematics
1 answer:
aliya0001 [1]3 years ago
3 0

Answer:

250ml understand the concept please

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Help me find the missing length pleaseeee
Alja [10]

35 / 5 = 7 ; also 49 /7  = 7

So

? = 8 x 7 = 56

Answer

Missing side length = 56

7 0
3 years ago
MiKiyah invested $2,500 in a simple interest account for 2 years. At the end of the 2 years, she has earned $75 in interested. W
forsale [732]

Answer:

if $178 $178 interest was earned in 2 2 years at an interest rate of 4%

Step-by-step explanation:

XD i tried

3 0
2 years ago
What is the value of X? <br> X= <br><br> B=75<br> C=50<br> A=x <br><br> Thank u! Sorry i'm dumb:(
murzikaleks [220]
Angels on a triangle is 180°
so you add 75 and 50 which gives you 125 then u take away that by 180 to find x
and that your answer
I'm going to let you work it out since its easy question
8 0
3 years ago
Evaluate -8w + 3z when w = 2.2 and z = -9.1.
atroni [7]
-8w+3z
w=2.2
z=-9.1

-8(2.2)+3(-9.1)
-17.6-27.3
-44.9

The answer is -44.9
8 0
3 years ago
Read 2 more answers
To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo
mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}

Given:

\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25

Confidence level = 80%

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0
3 years ago
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