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Alex73 [517]
4 years ago
12

I

Mathematics
1 answer:
Stolb23 [73]4 years ago
6 0

Answer:

The deep of the sand will be 3.5 feet

Step-by-step explanation:

step 1

Find out the area of the court plus a 10-foot boundary around the  court for safety

A=(30+10+10)(60+10+10)\\A=(50)(80)\\A=4,000\ ft^2

step 2

Find the deep of the sand

we know that

The volume of the sand is equal to

V=Ah

where

A is the area of the base

h is the height or deep of the sand

substitute the given values

14,000=(4,000)h

Solve for h

h=14,000/4,000=3.5\ ft

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A temperature record in Antarctica was -120.the temperature recorded in the Sahara desert was 129.how many degrees warmer is 129
allochka39001 [22]

129 is 249 degrees warmer than -120 because -120+120=0 and then you add 129 to 0 which is 129. that means you add 120 and 129 to get 249

7 0
3 years ago
What is the length of the hypotenuse
tankabanditka [31]

Answer:

10

Step-by-step explanation:

8 to the second power is 64

6 to the second power is 36

36+64=100

the square root of 100 is 10

so 10 is the length of the hypotenuse

Hope this helps!

5 0
3 years ago
Help please! any help is appreciated
maria [59]

Answer:

Step-by-step explanation:

6.

P(even)=4/8=1/2

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7.

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5 0
3 years ago
4x - 3y = 12<br> 4x - 5y = -4<br> Solve using Elimination
mr_godi [17]

Answer:

{ \rm{4x - 3y = 12 -  -  -  \{eqn(a) \}}} \\ { \rm{4x - 5y =  - 4 -  -  -  \{eqn(b) \}}}

• subtract eqn(b) from eqn(a);

{ \underline{ \rm{  - \binom{4x - 3y = 12}{4x - 5y =  - 4} }}} \\ { \rm{0x + 2y = 16}} \\  \\ { \rm{2y = 16}} \\  \\ { \boxed{ \tt{ \:  \: y = 8 \:  \:   }}} \\

• find x :

{ \rm{4x - 3y = 12}} \\ { \rm{4x - 3(8) = 12}} \\ { \rm{4x = 36}} \\  \\ { \boxed{ \tt{ \:  \: x = 9 \:  \: }}}

8 0
3 years ago
Read 2 more answers
Math<br><br><br> is my answer correct??
matrenka [14]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution ~

The given points are : (-7 , -4) and (1 , 1)

now, let's use distance formula to find the distance between them !

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:\sqrt{(x_2 - x_1)² +( y_2 - y_1)² }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{( - 7 - 1) {}^{2}  + ( - 4  - 1) {}^{2} }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{( - 8)² +(  - 5)² }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{64 + 25}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sqrt{89}

3 0
2 years ago
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