PLEASE I NEED HELP FROM ANYONE!! THANKS!

The length of the line segment containing the points (1,7) and (5,5)

ArbitrLikvidat [17]

Answer:

True

Step-by-step explanation:

Let A denotes the point (1,7)

Let B denotes the point (5,5)

We are supposed to find The length of the line segment containing the points

Formula : $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(x_1,y_1)=(1,7)\\(x_2,y_2)=(5,5)\\ d = \sqrt{(5-1)^2+(5-7)^2}\\ d = \sqrt{4^2+(-2)^2}\\ d = \sqrt{4^2+(-2)^2}\\d=4.47$

So,The length of the line segment containing the points (1,7) and (5,5) is 4.47 units is true.

Hence Option A is true

4 0

3 years ago

-4 -12

Zarrin [17]

Answer:

Slope(m)=3

Y-intercept= 0

y = 3x +0

Proportional

Step-by-step explanation:

m = -6--12/-2--4

m=6/2

m=3

-12 = 3(-4) + b

-12 = -12 + b

0=b

3 0

3 years ago

Read 2 more answers

ASAP The ratio of the width to the length of a ratio is1:3 which of the following ratio represents a rectangle with an equivalen

Soloha48 [4]

Take whatever side lengths you have and divide that number by 1/3 in your calculator and what number is shown after doing this is the answer

4 0

3 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

3 years ago

What is two more than 4 times a number is -18 translated and solved

Brrunno [24]

Answer:

n=-5

Step-by-step explanation:

Let "n" represent the unknown number.

So, the equation asks for 4n and two more, or +2, that is all equal to -18.

So, your equation will be:

$4n+2=-18$

First, subtract 2 from both sides:

$4n+2-2=-18-2\\4n=-20$

Then, divide both sides by 4:

$\frac{4n}{4}=\frac{-20}{4}\\n=-5$

Therefore, n=-5.

3 0

3 years ago