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2 years ago

PLEASE I NEED HELP FROM ANYONE!! THANKS!

Mathematics

1 answer:

Evgesh-ka [11]2 years ago

7 0

B

W
The whole circle is pi r^2= 18 times 18 is 324 pi minus the white part

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6. Complete the two-column proof.

olya-2409 [2.1K]

Answer:

Given: $\frac{x}{6} + 2 = 15$ ......[1]

To prove : x =78

Subtraction property states that you subtract the same number to both sides of an equation.

Subtract 2 from both sides of an equation [1];

$\frac{x}{6} + 2 - 2= 15 -2$

Simplify:

$\frac{x}{6} = 13$ ......[2]

Multiplication property states that you multiply the same number to both sides of an equation.

Multiply 6 to both sides of an equation [2];

$\frac{x}{6} \times 6 = 13 \times 6$

Simplify:

$x = 78$ proved!

Statement Reason

1. $\frac{x}{6} + 2 = 15$ Given

2. $\frac{x}{6} = 13$ Subtraction property of equality

3. $x = 78$ Multiplication property of equality

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Identify the figure that illustrates "A reflection in line k."

dlinn [17]

The 1st figure is correct, the 4th one seems very similar to the 1st one. But the red shape is closer to line k. So the 1st one is correct

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Which choices are equivalent to the expression below √16 • √9

Luda [366]

Answer:

Step-by-step explanation:

=> √16 • √9

=> Take square roots

=> 4 • 3

=> 12

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What percent is equivalent to 0.25?

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Answer:

25%

Step-by-step explanation:

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Using Newton's Law of Cooling. You are a medical examiner called to an abandoned house in which a dead body has been discovered.

Artyom0805 [142]

A) The differential equation comes from the fact that the rate of temperature change is proportional to the difference in temperatures.
$\frac{dT}{dt} = \alpha(T -52)$

B) Find general solution by separating variables and integrating $\int\frac{dT}{T-52} = \alpha \int dt \\ ln (T-52) = \alpha t + C \\ T = C e^{\alpha t} +52$ :

C) Initial condition is t=0, T = 87
$87 = C +52 \\ C = 35$

D) Total time elapsed is 10 minutes, new temperature is 84
$84 = 35 e^{10\alpha} +52$
solve for alpha
$e^{10\alpha} =\frac{32}{35} \\ \alpha = \frac{ln(32/35)}{10} \\ \alpha = -.00896$

E) Temperature function is:
$T = 35 e^{-.00896 t} +52$
solving for t
$t = \frac{ln (\frac{T-52}{35})}{-.00896}$
Plug in T = 98.6
$t = -31.95$

This is approximately 32 minutes before he arrived or about 1:20 AM

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