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nadezda [96]
3 years ago
10

What is the surface area of this cylinder ( rounded to nearest tenth)​

Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:

Step-62.8m^2

Step-by-step explanation:

Surface area of a cylinder =  

r = 2m, h = 3m

= 62.83185

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What is the area of ABC?
notsponge [240]

Let D be the Intersection of Height of the Triangle and Base of the Triangle BC

From the Figure, We can notice that Triangle ADB is a Right angled Triangle.

We know that, In a Right angled Triangle :

\bigstar  (Hypotenuse)² = (First Leg)² + (Second leg)²

In Triangle, ADB : AB is the Hypotenuse, AD is the First leg and BD is the Second leg

Given : AB = 15 and BD = 9

Substituting the values, We get :

:\implies  (15)² = (AD)² + (9)²

:\implies  225 = (AD)² + 81

:\implies  (AD)² = 225 - 81

:\implies  (AD)² = 144

:\implies  (AD)² = (12)²

:\implies  AD = 12

We know that, In a Right angled Triangle :

\bigstar\;\;\boxed{\mathsf{Tan\theta = \dfrac{Opposite\;Side}{Adjacent\;Side}}}

Now, Consider Triangle ADC : With respect to 45° Angle, AD is the Opposite Side and DC is the Adjacent Side

:\implies \mathsf{In\;Triangle\;ADC,\;Tan45^{\circ} = \dfrac{AD}{DC}}

\mathsf{:\implies 1 = \dfrac{12}{DC}}

:\implies  DC = 12

:\implies  Total Length of the Base (BC) = BD + DC

:\implies  Total Length of the Base (BC) = 9 + 12

:\implies Total Length of the Base (BC) = 21

We know that, Area of the Triangle is given by :

\bigstar\;\;\boxed{\mathsf{Area = \dfrac{1}{2} \times Base \times Height}}

In Triangle, ABC : AD is the Height and BC is the Base

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times BC \times AD}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times 21 \times 12}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = (21 \times 6)}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = 126}

7 0
3 years ago
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