1) Coordinates of point C.
C is the midpoint of the segment AB.
So, its coordinates are:
x = (2 + 8) / 2 = 10/2 = 5
y = (3 + 1) / 2 = 4 / 2 = 2
So, the point C is (5,2)
2) Slope of the segment CD.
First, calculate the slope of the segment AB, m
m = Δy / Δx = (y2 - y1) / (x2 - x1) = (3 -1) / (2 - 8) = 2 / ( -6) = - 1/3
Second, calculate the slope of CD,m', as the negative inverse of m:
m' = - 1 / m = - 1 / (-1/3) = 3
Slope of segment CD is 3.
3) Possible coordinates of point D.
You have to use this three data:
Point C: (5, 2)
length CD = √10
slope CD = 3
Call the point D (x,y)
Use fhe equation for the slope: [y - 2] / [x - 5] = 3
=> y - 2 = 3( x- 5)
=> y = 3x - 15 + 2
=> y = 3x - 13
Use the equation for the distance: (x - 5)^2 + (y - 2)^2 = (√10)^2
Expand the parenthesis:
x^2 - 10x + 25 + y^2 - 4y + 4 = 10
Replace y with 3x - 13
x^2 - 10x + 25 + (3x - 13)^2 - 4(3x - 13) + 4 = 10
x^2 - 10x + 25 + 9x^2 - 78x + 169 - 12x + 52 + 4 - 10 = 0
Combine like terms:
10x^2 - 100x + 240 = 0
Simplify by 10:
x^2 - 10x + 24 = 0
Factor
(x - 6)(x - 4) = 0 => x = 6 or x = 4
Calculate y for both x-values:
y = 3(6) - 13 = 5 or y = 3(4) - 13 = - 1
Possible coordinates of point D: (6,5) and (4, -1).
Answer: 27
Step-by-step explanation:
use the formula for the area of circle and solve for r: A=pi r^2
2290.221=pir^2 <---divide by pi
729=r^2 <--- square root both sides
27=r
Answer:
Hepatitis C.
Step-by-step explanation:
Answer:
Equations
Step-by-step explanation:
16:
7 · (-3) = -21
-3 · 7 = -21
-21 ÷ 7 = -3
-21 ÷ (-3) = 7
17:
-4 · (-5) = 20
-5 · (-4) = 20
20 ÷ (-4) = -5
20 ÷ (-5) = -4
18:
1.5 · (-3) = -4.5
-3 · 1.5 = -4.5
-4.5 ÷ 1.5 = -3
-4.5 ÷ (-3) = 1.5
This is 7th grade?
Hope I helped :)
Answer:
For that particular polynomial your answer would be
x1=-5, x2=5