F(x) = k(x+2)(2x-1)(x-3), where k is some constant
= k(2x^3-3x^2-11x+6)
= k(-2x^3+3x^2+11x-6)
k defines some vertical stretch, so there are an infinitely many solutions for f(x).
Answer:
yes its 6/3
Step-by-step explanation:
im just smart
Answer:

Step-by-step explanation:
Every inscribed right triangle has its hypotenuse as the same size of the Diameter. Assuming that, this is the case check the picture below.
So the hypotenuse= D=2R=12
- Shaded Area = Area of the Circle- Area of the Triangle

Finding the Triangle base via the Pythagorean Theorem

Now plugging in the base of the triangle on that formula:

Finally,
Shaded Area =
The answer is 4.968 so rounded it would be 5.