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2 years ago

Find the difference. Write your answer in scientific notation. (2.4 x 10^-1) - (5.5 x 10^-2) =

Mathematics

1 answer:

tekilochka [14]2 years ago

7 0

Answer:

0.185 Step-by-step explanation:

(2.4 x 10^-1) - (5.5 x 10^-2)

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0.24-0.055= 0.185

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What is the product of z1 and z2 if

MaRussiya [10]

Answer:

308[cos(45) + isin(45)]

Step-by-step explanation:

z1×z2:

Modulus: r1 × r2

= 7×44 = 308

Argument: theta1 + theta2

= -70 + 115 = 45

z1z2 = 308[cos(45) + isin(45)]

z1z2 = 154sqrt(2) + (i)154sqrt(2)

sqrt: square root

8 0

3 years ago

Out of 100 people sampled, 42 had kids. Based on this, construct a 99% confidence interval for the true population proportion of

maksim [4K]

Answer:

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

Out of 100 people sampled, 42 had kids.

This means that $n = 100, \pi = \frac{42}{100} = 0.42$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.293$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 + 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.547$

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

7 0

2 years ago

Graph a line that contains the point ( 3 , -6) and has a slope of 1/2

irina [24]

You need to physically draw that on a graph

3 0

2 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

2 years ago

Class 1 and class 2 have a total of 630 house points. Class 1 have double the number of house points that class 2 have. How many

Wewaii [24]

Answer:

Class 2 has 210 house points.

Step-by-step explanation:

630/3 = 210

1 = 210 x 2 = 420

2 = 210

420 + 210 + 630

6 0

1 year ago

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