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jeka94
3 years ago
8

A student needs to print pamphlets for an activities fair. If the printer takes 3 minutes to print a pamphlet, which inequality

represents
the possible number of pamphlets, p, the student can expect the printer to print in more than 30 minutes?
.
O 3p 30
Mathematics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

3p <_30

Step-by-step explanation:

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2 sin^2 (x) + 3 sin (x) + 1 = 0<br> help me find the solution
Fed [463]

Answer:

Step-by-step explanation:

\[2~ sin^2 x+3sin x+1=0\]

\[2sin^2x+2sin x+sin x+1=0\]

2sinx(sin x+1)+1(sin x+1)=0

(sin x+1)(2 sin x+1)=0

either sin x+1=0

sin x=-1=sin 3π/2=sin (2nπ+3π/2)

x=2nπ+3π/2,where n is an integer.

or 2sin x+1=0

sin x=-1/2=-sin π/6=sin (π+π/6),sin (2π-π/6)=sin (2nπ+7π/6),sin (2nπ+11π/6)

x=2nπ+7π/6,2nπ+11π/6,

where n is an integer.

7 0
3 years ago
Any number raised to the zero power always equals
Otrada [13]
Always equals 1. Always!
7 0
3 years ago
Read 2 more answers
Một khối kim loại có thể tích 3,2cm3 và cân nặng 22,4g. Hỏi một khối kim loại cùng chất có thể tích là 4,5cm3 cân nặng bao nhiêu
Ymorist [56]

Answer:

Một cm3 của khối kim loại đó cân nặng số gam là:

22,4:3,2=7(g)

Một khối kim loại cùng chất có thể tích là 4,5cm3 cân nặng số gam là:

7x4,5=31,5(g)

Step-by-step explanation:

6 0
2 years ago
Who can solve this in 1 min 5678÷78
andreev551 [17]

It is 72.7948718

~Hope that helped!~

~Izzy <3

5 0
3 years ago
Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial function. In y
bekas [8.4K]
F(x) = 2^x; h(x) = x^3 + x + 8

Table


x      f(x) =  2^x             h(x) = x^3 + x + 8

0      2^0 = 1                0  + 0 + 8 = 8

1     2^1 = 2                 1^3 + 1 + 8 = 10

2      2^2 = 4                2^3 + 2 + 8 = 8 + 2 + 8 = 18

3      2^3 = 8                3^3  + 3 + 8 = 27 + 3 + 8 = 38

4      2^2 = 16              4^3 + 4 + 8 = 76

10    2^10 = 1024       10^3  +10 + 8 = 1018

 9      2^9 =   512        9^3 + 9 + 8 = 729 + 9 + 8 = 746

Answer: an approximate value of 10
7 0
3 years ago
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