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Contact [7]
3 years ago
9

A striped ball has 6 purple and 5 yellow stripes which are all the same size. The radius of the spherical ball is 13 in. The sur

face area of purple stripes is _____ in2.
Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

https://bridgeprepriverview.com/ourpages/auto/2020/2/4/54307042/Student%20textbook.pdf

their is the link for the answers.

Step-by-step explanation:

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292,201,338 possible combinations powerball numbers

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if your talking about altogether then 292,201,338 but if its specific you need to upload a screenshot of the options

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What is the slope of the line?help pls
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1

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Expand and simplify (x-3)(2x+1)(x+1)
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2 3 − 3 2 − 8 − 3

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3 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

6 0
3 years ago
Pa help nmn po need lang po talaga
LekaFEV [45]

Answer:

Pa follow mona at pa brienlist

Step-by-step explanation:

Please

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3 years ago
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