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Luda [366]
3 years ago
5

After working for a few years, the instructor has $3,500 saved for rent. He rents an apartment that costs $275 a month. Which gr

aph represents the equation of the scenario?
A graph has month on the x-axis and saved (money) on the y-axis. Points are at (0, 350), (1, 700), (2, 800), (3, 1000), (4, 1,400).
A graph has month on the x-axis and saved (money) on the y-axis. Points are at (1, 3500), (2, 3,000), (3, 2,800), (4, 2,700).
A graph has month on the x-axis and saved (money) on the y-axis. Points are at (0, 3,500), (1, 3,200), (2, 29,00), (3, 2,600), (4, ,300).
A graph has month on the x-axis and saved (money) on the y-axis. Points are at (1, 350), (2, 700), (3, 900), (4, 1200).
Mathematics
2 answers:
bulgar [2K]3 years ago
8 0

Answer:

The third graph

Step-by-step explanation:

kondaur [170]3 years ago
5 0
Answer: A graph has month on the x-axis and saved (money) on the y-axis. Points are at (1, 3500), (2, 3,000), (3, 2,800), (4, 2,700)
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Answer:

The answer is (d) ⇒ pq^{2}r\sqrt[3]{pr^{2}}

Step-by-step explanation:

* To simplify the cube roots:

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 then we divide the power by 3 to cancel the radical

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∵ \sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}

∴ p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}

∵ p^{\frac{1}{3}}=\sqrt[3]{p}

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∴ p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})

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