Answer:
2Na2O2+2H2O⟶O2+4NaOH
2×78g 32g
156g of Na2O2 produces 32g of O2,
12g of Na2O2 produces =15632×12=10.66g.
Density of O2 at NTP=1.428g/mL.
DensityMass=Vol.
1.42810.66=7.46mL
Vol. of O2 at NTP is 7.46mL.
Explanation:
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Answer:
B. 0.55 M
Explanation:
Step 1: Given data
- Moles of calcium chloride (solute): 1.5 mol
- Volume of solution: 2.75 M
Step 2: Calculate the molarity of the aqueous solution
The molarity is a way to express the concentration of a solution. It is equal to the quotient between the moles of solute and the liters of solution.
M = moles of solute / liters of solution
M = 1.5 mol / 2.75 L = 0.55 mol/L = 0.55 M
Answer:
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Explanation:
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