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loris [4]
2 years ago
7

What are the hazards, if any of the reactants AgNO3, and K2CrO4?

Chemistry
1 answer:
Mandarinka [93]2 years ago
3 0
This is what i wrote in my notebook: (for AgNO3)
<span>Health Hazards Acute and Chronic:  ACUTE:
INHALATION - MAY CAUSE SEVERE IRRITATION TO MUCOUS MEMBRANES.
SKIN - MAY CAUSE SEVERE IRRITATION.
EYE - MAY CAUSE SEVERE IRRITATION.
CHRONIC: INHALATION, SKIN & INGESTION - MAY CAUSE ARSYRIA. Explanation of Carcinogenicity:THIS COMPOUND CONTAINS NO INGREDIENTS AT CONCENTRATIONS OF 0.1% OR GREATER THAT ARE CARCINOGENS OR SUSPECT CARCINOGENS.

</span><em><u>AgNO3 + K2CrO4 = Ag2CrO4 + KNO3</u></em>

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What are two energy alternatives to fossil fuels?
Alex17521 [72]

Explanation:

solar and energy i had to answer this one before

5 0
1 year ago
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If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
goldfiish [28.3K]
The balanced chemical reaction:

<span>Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
</span>
We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.

9.85 g Cu ( 1 mol Cu / 63.55 g Cu ) = 0.15 mol Cu
31.0 g AgNO3 ( 1 mol AgNO3 / 169.87 g AgNO3 ) = 0.18 mol AgNO3

The limiting reactant is AgNO3.

0.18 mol AgNO3 ( 1 mol Cu(NO3)2 / 2 mol AgNO3 ) (187.56 g / 1 mol) =16.88 g Cu(NO3)2

0.15 mol Cu - 0.18 mol AgNO3 ( 1 mol Cu / 2 mol AgNo3) = 0.06 mol Cu excess

<span>0.06 mol Cu ( 63.55 g Cu / 1 mol Cu ) = 3.81 g Cu excess</span>
3 0
3 years ago
Read 2 more answers
If i add 25 mL of water to 125 mL of a 0.15 M NaOH solution, what will the molarity of the diluted solution be ?
marshall27 [118]
1000 mL=1L

25 mL = 0.025 L
125 mL = 0.125 L

M1V1=M2V2
0.15(0.125) = M2(0.025)
0.01875 = M2(0.025)
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6 0
2 years ago
How many grams of NO can be produced from the following reaction if 68.2 grams of NO2 is consumed?
Semenov [28]

Answer:

Option 4. 14.8 g

Explanation:

3NO2 + H2O → 2HNO3 + NO

First let us calculate the molar mass of NO2 and NO. This is illustrated below;

Molar Mass of NO2 = 14 + (2x16) = 14 + 32 = 46g/mol

Mass of NO2 from the question = 3 x 46 = 138g.

Molar Mass of NO = 14 +16 = 30g/mol

From the equation,

138g of NO2 reacted to produce 30g of NO

Therefore, 68.2g of NO2 will react to produce = (68.2 x 30)/138 = 14.8g of NO.

3 0
3 years ago
(9443+45−9.9) (9443+45−9.9) ×8.4× 10 6
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Booooooommmm!.................

6 0
3 years ago
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