What are the hazards, if any of the reactants AgNO3, and K2CrO4?

1 answer:

3 0

This is what i wrote in my notebook: (for AgNO3)
Health Hazards Acute and Chronic: ACUTE:
INHALATION - MAY CAUSE SEVERE IRRITATION TO MUCOUS MEMBRANES.
SKIN - MAY CAUSE SEVERE IRRITATION.
EYE - MAY CAUSE SEVERE IRRITATION.
CHRONIC: INHALATION, SKIN & INGESTION - MAY CAUSE ARSYRIA. Explanation of Carcinogenicity:THIS COMPOUND CONTAINS NO INGREDIENTS AT CONCENTRATIONS OF 0.1% OR GREATER THAT ARE CARCINOGENS OR SUSPECT CARCINOGENS.

AgNO3 + K2CrO4 = Ag2CrO4 + KNO3

You might be interested in

A cyclist rode at an average speed of 10 mph for 15 miles. How long was the ride?

xxMikexx [17]

If the cyclist rode at an average speed of 10mph for 15 miles...

we can solve by dividing the distance by the speed to get time using the equation...

Δspeed = Δdistance / Δtime

Δtime = Δdistance / Δspeed

Δtime = 15 miles / 10 mph = 1.5 hours

7 0

3 years ago

Read 2 more answers

What is smaller? WHY? a Atom or Electron

tresset_1 [31]

Electron, because they’re about 1/2000 the mass of a proton or nuetron

6 0

2 years ago

Two alcohols, isopropyl alcohol and propyl alcohol, have the same molecular formula, C3H8O. A solution of the two that is two-th

iris [78.8K]

Answer:

Since both components of these solutions have the same molar mass, mole fractions would be the same as mass fractions.

0.110 atm = (2/3)(Pi) + (1/3)(Pn) [1]

0.089 atm = (1/3)(Pi) + (2/3)(Pn) [2]

2*[1] - [2]:

(2)(0.110) - 0.089 atm = Pi

Pi = 0.131 atm

2*[2] - [1]:

(2)(0.089) - 0.110 atm = Pn

Pn = 0.068 atm

The hydroxyl (-OH) group on the end of a longer 1-propanol molecule makes it more polar than IPA. It follows that the intermolecular forces between 1-propanol are stronger than those of IPA and thus the vapor pressure of 1-propanol should be lower than IPA.

Explanation:

5 0

3 years ago

The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this

nevsk [136]

Answer:

$5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}$

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

$Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }$