Answer:
100% pea plants will be with green pod and with round seeds.
Explanation:
As per the question given, a homozygous pea plant having green pod (gg) and round seeds (WW) is crossed with a pea plant having homozygous green pod (gg) and heterozygous round seeds(Ww). A pea plant homozygous for green pod and round seeds (ggWW) will produce one type of gametes having alleles (gW), whereas, a pea plant homozygous for green pod and heterozygous for round seeds(ggWw) will produces two type of gametes having alleles gW and gw. On crossing, phenotypically, they will produce all pea plants with green pod and round seeds. But genotypically, 50% of green pod pea plants with homozygous round seeds and 50% of green pod pea plants with heterozygous round seeds.
Explanation:
The correct answer would be a because the line hasn't reached 1.5 yet (longest line between each numbers represent .5)
Answer:
it will be 4M because molarity = no.of mole/volume
The balanced chemical reaction:
K2SO4 + O2 = 2KO2 + SO2
Assuming that the reaction is complete, all of the potassium sulfate is consumed. We relate the substances using the chemical reaction. We calculate as follows:
7.20 g K2SO4 ( 1 mol / 174.26 g) ( 1 mol O2 / 1 mol K2SO4 ) ( 32 g / 1 mol ) = 1.32 g O2 consumed in the reaction.