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Answer:
0.84kg of gatorade powder is needed.
Explanation:
From the question given above, we were told that the team manager mixes 0.6kg of gatorade powder with 5 gallons of water.
Now, to obtain the desired amount of the powder of gatorade needed for 7 gallons of water, we simply do the following:
If 0.6kg of gatorade powder required 5 gallons of water,
Then Xg of gatorade will require 7 gallons of water i.e
Xg of gatorade = (0.6 x 7)/5
Xg of gatorade = 0.84kg
Therefore, to maintain the same gatorade mixture, the team manager must mix 0.84kg of gatorade powder with the 7 gallons of water.
Answer : The freezing point of the solution is, 260.503 K
Solution : Given,
Mass of methanol (solute) = 215 g
Mass of water (solvent) = 1000 g = 1 kg (1 kg = 1000 g)
Freezing depression constant = 
Formula used :
where,
= freezing point of water = 
= freezing point of solution
= freezing point constant
= mass of solute
= mass of solvent
= molar mass of solute
Now put all the given values in the above formula, we get
By rearranging the terms, we get the freezing point of solution.
Therefore, the freezing point of the solution is, 260.503 K
Answer:
18.
Explanation:
1) according to the reaction (M(Fe)=56; M(O₂)=32; V₀=22.4):
4Fe+3O₂⇒2Fe₂O₃; - ν(O₂)=0.75*ν(Fe);
2) ν(Fe)=m(Fe)/M(Fe)=60/56≈1.071 [mol];
3) ν(O₂)=0.75*1.071=0.804 [mol];
4) V(O₂)=V₀*ν(O₂); ⇒ V(O₂)=22.4*0.804=18 [lit].
The answer to your question is A.
