The standard ambient temperature and pressure are
Temperature =298 K
Pressure = 1atm
The density of gas is 1.5328 g/L
density = mass of gas per unit volume
the ideal gas equation is
PV = nRT
P = pressure = 1 atm
V = volume
n = moles
R= gas constant = 0.0821 Latm/mol K
T = 298 K
moles = mass / molar mass
so we can write
n/V = density / molar mass
Putting values
![Pressure=\frac{nRT}{V}=\frac{massXRT}{VXmolarmass}](https://tex.z-dn.net/?f=Pressure%3D%5Cfrac%7BnRT%7D%7BV%7D%3D%5Cfrac%7BmassXRT%7D%7BVXmolarmass%7D)
![Pressure=\frac{densityXRT}{molarmass}](https://tex.z-dn.net/?f=Pressure%3D%5Cfrac%7BdensityXRT%7D%7Bmolarmass%7D)
![molarmass=\frac{densityXRT}{Pressure}=\frac{1.5328X0.0821X298}{1}=37.50](https://tex.z-dn.net/?f=molarmass%3D%5Cfrac%7BdensityXRT%7D%7BPressure%7D%3D%5Cfrac%7B1.5328X0.0821X298%7D%7B1%7D%3D37.50)
Thus molar mass of gas is 37.50g/mol
Answer:
2341, last option is the correct choice.
Explanation:
Boiling points of the given compounds are given as:
![CH_4=-161.5\:C^{\circ}\\\\C_4H_{10}=-1\:C^{\circ}\\\\CH_2Cl_2=39.6\:C^{\circ}\\\\H_2O=100\:C^{\circ}](https://tex.z-dn.net/?f=CH_4%3D-161.5%5C%3AC%5E%7B%5Ccirc%7D%5C%5C%5C%5CC_4H_%7B10%7D%3D-1%5C%3AC%5E%7B%5Ccirc%7D%5C%5C%5C%5CCH_2Cl_2%3D39.6%5C%3AC%5E%7B%5Ccirc%7D%5C%5C%5C%5CH_2O%3D100%5C%3AC%5E%7B%5Ccirc%7D)
Best Regards!
Answer:19.2
Explanation: if see you have to times it and show it with times