Set this up as follows...
12x - 10 = 7x + 20
solve for x
X is 6
sub VW=7X with 7•6
VW=42
check by subbing also for UW
72 - 10 is 62
uV plus VW equals 62. it checks out.
We need to look at the number after the tenth, called the 'hundredth'. If the hundredth is 5 or above, we must change the hundredth to 0 and make the tenth one higher.
In this case, the hundredth is 9 and is above 5, so it becomes 0 and the tenth moves higher to become 9.
The number will now be 1.9
MB=(1/2)AB
(1/2)126=63
63=8x+7
56=8x
x=7
Answer:
Step-by-step explanation:
The resulting course vector (magnitude 300, angle = 160° with the positive x axis (= 290° bearing)) with components (300cos160,300sin160) is the sum of the vector of the actual flight vector and the wind vector.
The wind vector has magnitude 18 and direction 46° with the positive x-axis ( it blows from - 134° with the positive x axis (= 224° bearing) into direction 46° with the positive x-axis). So its components are (18cos46,18sin46).
The course that the plane has to steer is :
(300cos160,300sin160)-(18cos46,18sin46)
=(300cos160 - 18cos46, 300sin160 - 18sin46)
=(-294.41, 89.6579)
The magnitude of this steering vector is = 307.749 knots and its direction will be:
with the negative x-axis (286.94° bearing).
Thus, the drift angle will be=290° - 286.94° = 3.06°.
Answer:
(2^2)3 = 2^6
(2^3)2 = 2^6
Step-by-step explanation:
There are various exponent rules. The problems that you were assigned must follow the power of a power rule:
(x^a)^b = x^a*b
Exponents must be multiplied according to this rule. Hope this helps.