(PLEASE HELP)
1 answer:
You might be interested in
The functions are 
and g(t)=5.2t+20,
are both functions which give the heights of cannonballs thrown from 2 different cannons.
A.
g(3)=5.2(3)+20=31.6
g(4)=5.2(4)+20=40.8
g(5)=5.2(5)+20=46
g(6)=5.2(6)+20=51.2
up to the 5th second, the ball from H is higher than the one from g,
then from the 6th second the ball from H is lower than the ball from g,
this means that the solution of H(t)=g(t), is between the 5th and 6th seconds.
B. The solution of part A means that during the 3rd, until it falls, the ball from H is falling to the ground, but it is still higher than the ball g which is rising, until a point between the 5th and 6 th seconds, where the balls are at the same height for just one instant, then the ball H continues falling, while g rises up for a few more second.
are both functions which give the heights of cannonballs thrown from 2 different cannons.
A.
g(3)=5.2(3)+20=31.6
g(4)=5.2(4)+20=40.8
g(5)=5.2(5)+20=46
g(6)=5.2(6)+20=51.2
up to the 5th second, the ball from H is higher than the one from g,
then from the 6th second the ball from H is lower than the ball from g,
this means that the solution of H(t)=g(t), is between the 5th and 6th seconds.
B. The solution of part A means that during the 3rd, until it falls, the ball from H is falling to the ground, but it is still higher than the ball g which is rising, until a point between the 5th and 6 th seconds, where the balls are at the same height for just one instant, then the ball H continues falling, while g rises up for a few more second.