Answer:
Step-by-step explanation:(a)
1.65p+1.36j=118.17 and p+j=79
We can say p=79-j and sub this value in first equation
1.65(79-j)+1.36j=118.17
130.35-1.65j+1.36j=118.17
-0.29=-12.18
j=42, p=79-j, p=79-42=37
(b)
1.65(37)=61.05 and 1.36(42)=57.12
Sanchez class earned more selling pies.
(c)
61.05-57.12=3.93
So Sanchez class made $3.93 more than Kelley class.
What I would do:
5x + 10y = 35
Divide everything by 5.
x + 2y = 7
x = 7 - 2y
Now plug "x" into either one of the equations.
2(7-2y) + 5y = 15
14 - 4y + 5y = 15
14 + y = 15
y = 1
Now, solve for x by plugging in y into either one of the equations.
2x + 5y = 15
2x + 5 =15
2x = 10
x = 5
So x is 5 and y is 1.
Check by plugging in the values into the other equation.
5x + 10y = 35
5(5) + 10(1) = 35
25 + 10 = 35
35 = 35
The values are correct so, the answer for this problem is B (5, 1).
I would recommend "Introduction to Linear Algebra," by Gilbert Strang. It is a compact but very helpful textbook reference written by a well-known MIT professor. There is a corresponding online MIT course that is free, so that's a bonus. I am currently using it to study linear algebra with no class or previous experience, and I think it does a solid job of explaining things. Each section in the book has a set of questions for you to work through, and answers to selected questions appear in an appendix at the end of the book.
Hope this helps!
Using proportions, it is found that there is a 0.54 = 54% probability that a randomly selected household owns a cat.
<h3>What is a proportion?</h3>
A proportion is a fraction of total amount.
In this problem, the proportions associated with owning a cat are given by:
- 70% of 60%(also have a dog).
- 30% of 40%(do not have a dog).
Hence:
p = 0.7(0.6) + 0.3(0.4) = 0.42 + 0.12 = 0.54.
0.54 = 54% probability that a randomly selected household owns a cat.
More can be learned about proportions at brainly.com/question/24372153
Answer:
5 , 6, 2
Step-by-step explanation:
cause they da same
