<span>Rectangle with vertexes of (4,4), (-4,4), (4,10), and (-4,10)
I can't do your graph for you, but I can help with the coordinates of the final polygon. In general to scale (x,y) by s centered at (a,b) that would mean that (x,y) maps to ((x-a)*s+a, (y-b)*s+b). And since we've been given (a,b) = (0,0), the mapping simplifies to (x,y) maps to (x*s, y*s). So let's do it:
Point (2,2) ==> (2*2,2*2) = (4,4)
Point (-2,2) ==> (-2*2,2*2) = (-4,4)
Point (2,5) ==> (2*2,5*2) = (4,10)
Point (-2,5) ==> (-2*2,5*2) = (-4,10)
So your desired polygon is a rectangle with vertexes of (4,4), (-4,4), (4,10), and (-4,10)</span>
Your scaling in the x direction is OK, but you didn't scale in the y direction properly. Hint. Scale each vertex of the original rectangle independently to construct the scaled rectangle. I see the original points and their scaling by 2 as (2,2) - Scales to (2*2, 2*2) = (4,4) OK in your drawing. (-2,2) - Scales to (-2*2, 2*2) = (-4,4) OK in your drawing. (2,5) - Scales to (2*2, 5*2) = (4,10) Error in your drawing. (-2,5) - Scales to (-2*2, 5*2) = (-4,10) Error in your drawing.
t = -b/(2a) = -16/(2(-16)) = 1/2 . . . . . . where a=-16, b=16, c=32 are the coefficients of f(t)
The function can be factored to find the zeros.
f(t) = -16(t^2 -1 -2) = -16(t -2)(t +1)
The factors are zero for ...
x = -1 and x = +2
The ball is falling from its maximum height during the period (0.5, 2), so that is a reasonable domain if you're only interested in the period when the ball is falling.