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8_murik_8 [283]
3 years ago
13

Please help and show all work so I can fully understand it, thanks.

Mathematics
1 answer:
seraphim [82]3 years ago
4 0

Answer:

\frac{1}{m-4}

Step-by-step explanation:

\frac{\frac{4m-5}{m^4 -7m^3 +12m^2}}{\frac{4m-5}{m^3 -3m^2}}

Factor the equation:

\frac{\frac{4m-5}{m^2(m^2 -7m+12)}}{\frac{4m-5}{m^2(m-3)}}

\frac{\frac{4m-5}{m^2(m-3)(m-4)}}{\frac{4m-5}{m^2(m-3)}}

Rewrite to suit the format of multiplying two fractions. Remember, dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second. A reciprocal of a fraction is when one switches the place of the numerator and the denominator, that is, the value on top (numerator), and the value on the bottom (denominator).

\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}

Simplify, take out common terms that are found on both the numerator and denominator

\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}

\frac{1}{m-4}

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