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3 years ago

Solve each of the following system of equations by substitution!!! x-5y=-49 y=-2x+1

Mathematics

1 answer:

saul85 [17]3 years ago

8 0

Answer:

(-4,9)

Step-by-step explanation:

substitute the given value for y into the first equation

x-5(-2x+1)=-49

distribute

x+10x-5=-49

add like terms

11x-5=-49

add 5 to both sides

11x=-44

divide both sides by 11

x=-4

now plug x into into the second equation

y=-2(-4)+1

y=8+1

add like terms

y=9

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3 years ago

Divide write the quotient in lowest terms. 3/5 divided by 2 1/2.

kotykmax [81]

Answer:

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Juli2301 [7.4K]

Answer:

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2 years ago

Apply division algorithm to find the quotient and remainder on dividing the polynomial 3 x^ + 4 x^ square + 6 x + 9 by x^ + 3x +

Ulleksa [173]

I suppose you mean

$\dfrac{3x^3+4x^2+6x+9}{x^2+3x+7}$

$3x^3=3x\cdot x^2$ , and if we multiply $x^2+3x+7$ by $3x$ we get $3x^3+9x^2+21x$ . Subtracting this from the numerator gives a remainder of $-5x^2-15x+9$ .

$-5x^2=-5\cdot x^2$ , and multiplying $x^2+3x+7$ by $-5$ gives $-5x^2-15x-35$ . Subtracting this from the previous remainder gives a new remainder of $44$ .

$44$ has no remaining factors of $x^2$ in it, so we're done, and

$\dfrac{3x^3+4x^2+6x+9}{x^2+3x+7}=\underbrace{3x-5}_{\rm quotient}+\dfrac{\overbrace{44}^{\rm remainder}}{x^2+3x+7}$

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4 years ago