Answer:
5 units
Step-by-step explanation:
According to the given statement Δ XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z' which means that each point in ΔXYZ is moved 4 units up and moved 3 units left.
To find the distance of each corresponding point we will use the Pythagorean theorem which states that the square of the length of the Pythagorean of a right triangle is equal to the sum of the squares of the length of other legs
The square of the required distance = 4^2+3^2 = 16+9 =25
By taking root of 25 we get:
√25 = 5
Thus, we can conclude that the the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ is 5 units.
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Answer:
can i have my brainliest i helped u on the other questions pls dude
Step-by-step explanation:
It is B might might be wing :/
Answer:
The first five terms are;
-3,-7,11,-29,69
Step-by-step explanation:
The recursive definition of the sequence is
, 
and 
.
When n=3, we obtain;
.
.
.
.
When n=4
.
.
When n=5
.
.
Therefore the first five terms are;
-3,-7,11,-29,69
