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3 years ago

Mike earn $34 in 4 hours on his job today he wants to know how much would he earn if he wants 10 hours tomorrow

2 answers:

8 0

Answer: 85$

Explanation:
An easy way to solve this is by putting this in a fraction format, I attached a picture showing this

max2010maxim [7]3 years ago

7 0

Answer:

85 dollars

Step-by-step explanation:

34/4=8.5

8.5*10=85

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What is the solution of the linear-quadratic system of equations? {y=x^2+5x−3 {y-x=2

Rina8888 [55]

Answer: the above stated equation is a quadratic equation

Step-by-step explanation:

Given the following equations

y = x^2 + 5x - 3....equation 1

y-x = 2

y = x + 2........equation 2

Let equation 1 equal equation 2

x^2 + 5x -3 = x + 2

Bringing the equation to one side and equating to zero

X^2 +5x - 3 -x -2 = 0

X2 + 5x -x -3 -2 = 0

X^2 + 4x -5

Solving the aquatic equation

(x + 5)(x -1) = 0

X + 5 = 0

X1 = -5

X- 1 = 0

X2 = 1

To prove:

Substitute the values for x1and x2 into the equation x^2 + 4x - 5 = 0

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3 years ago

What is the total weight in ounces of the four heaviest eggs?

Orlov [11]

Answer:

6 3/4 ounces

Step-by-step explanation:

4 0

3 years ago

4. In a sample of 1000 people, 130 can wiggle their ears. Two unrelated people are

Elina [12.6K]

Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.

The people are chosen from the sample without replacement, which is why the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.

In this problem:

1000 people means that $N = 1000$
130 can wiggle their ears, thus $k = 130$
Two are selected, thus $n = 2$ .

The probability that neither can wiggle his or her ears is P(X = 0), thus:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(0,1000,2,130) = \frac{C_{130,0}C_{870,2}}{C_{1000,2}} = 0.7568$

0.7568 = 75.68% probability that neither can wiggle his or her ears.

A similar problem is given at brainly.com/question/24826394

5 0

3 years ago

uppose that we have collected information on how much a sample of households spend on clothing per year. If we are 90% confident

Verizon [17]

Answer:

the chance that the population mean will either be less than $1,500 or above $2,100 is 10%

Step-by-step explanation:

We are 90% confident that the true population mean willl be between $1,500 and $2,100

This means that there is a 90% probability that the true population mean will be between $1,500 and $2,100.

So 100-90 = 10% probability that it is outside of this interval, that is, either be less than $1,500 or above $2,100.

So the correct answer is:

the chance that the population mean will either be less than $1,500 or above $2,100 is 10%

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3 years ago

A fashion designer wants to know how many new dresses women buy each year. A sample of 683 women was taken to study their purcha

Ulleksa [173]

The answer is I don’t know sorrry

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3 years ago